: Jaishree Soni
: CBSE Class 10 Science Previous Year Solved Paper Code 086 with Videos and Online Test Papers
: Poorav Publications
: 9789369912582
: 1
: CHF 6.60
:
: Naturwissenschaft
: English
: 130
: DRM
: PC/MAC/eReader/Tablet
: ePUB

We are pleased to present this comprehensive compilation of CBSE Class 10 Science Previous Year Solved Paper Code 086 with Videos and Online Test Papers. This book is thoughtfully designed to serve as a reliable and practical resource for students aiming to excel in their CBSE board examinations. It includes fully solved question papers based on the latest syllabus and examination pattern prescribed by CBSE.
Science is a subject that blends conceptual understanding with practical application. Students need clarity of concepts and effective answer-writing techniques to perform well. With this in mind, this book offers a collection of actual board exam papers, thoroughly solved by subject matter experts, to help students grasp the correct approach to answering different types of questions.
Key Features of the Book:
• Actual Board Question Papers: Includes authentic CBSE Class 10 Science question papers, providing real exam-level questions for targeted preparation.
• Detailed Solutions: Every question is accompanied by a step-by-step, well-explained answer to guide students on how to approach and structure their responses.
• Exam-Oriented Preparation: Helps students understand the pattern, difficulty level, and marking scheme followed by the board.
• Concept Clarity: Solutions are written in a simplified and easy-to-understand manner to enhance conceptual clarity and ensure better retention.
• Time Management Practice: Enables students to practice completing the paper within the allotted time, improving speed and accuracy.
• Last-Minute Revision Tool: An ideal book for quick and effective revision in the final weeks leading up to the exam.
• Performance Improvement: Solving these papers will help students identify weak areas and improve their confidence through self-assessment.
We are confident that this book will be a valuable asset for Class 10 students in their academic journey. By regularly practicing with these solved papers, students can not only enhance their exam performance but also build a strong conceptual foundation in Science, which will benefit them in higher classes and competitive exams.
We wish all students great success in their board exams and hope this book contributes meaningfully to their preparation.

Chapter 1: Previous Year Paper – 2021 (Term- I)


Time allowed: 2 hours MaximumMarks: 40

General Instructions:

Read the following instructions very carefully and strictly follow them:

1. This question paper comprises 15 questions. All questions are compulsory. (ii) (iii) (iv) (v) (vi) 1. 2. 3. 4.

2. This question paper is divided into three sections Section A, B and C.

3. SECTION A: Questions No. 1 to 7 are short answer type questions. Each question carries 2 marks.

4. Section B: Questions No. 8 to 13 are also short answer type questions. Each question carries 3 marks.

5. Section C: Questions No. 14 and 15 are case-based questions. Each question carries 4 marks.

6. Internal choices have been provided in some questions. Only one of the alternatives has to be attempted.

 

SECTION A

1. a.) Write the molecular formula of the following carbon compounds:

(i) Methane

Answer. The molecular formula of methane isCH₄.

(ii) Propane

Answer: The molecular formula of propane isC₃H₈.

b.) Carbon compounds have low melting and boiling points. Why?

Answer: Carbon compounds, particularly hydrocarbons, tend to have low melting and boiling points because:

i. They generally consist of molecules held together by weak intermolecular forces like van der Waals forces (dispersion forces).

ii. These forces are much weaker compared to covalent or ionic bonds, meaning less energy is required to break these forces and change the state of the compound (solid to liquid or liquid to gas).

2. The electrons in the atoms of two elements X and Y are distributed in three shells having 1 and 7 electrons respectively in their outermost shells.

(a) Write the group numbers of these elements in the Modern Periodic Table.

Answer:X: Since element X has 1 electron in its outermost shell, it belongs toGroup 1 (alkali metals) of the Modern Periodic Table.

Y: Since element Y has 7 electrons in its outermost shell, it belongs toGroup 17 (halogens) of the Modern Periodic Table.

(b) Write the molecular formula of the compound formed when X and Y combine with each other.

Answer: Element X (Group 1) will lose 1 electron to become positively charged (cation), and element Y (Group 17) will gain 1 electron to become negatively charged (anion).

Therefore, they will combine in a 1:1 ratio to form a neutral compound. The molecular formula of the compound formed isXY.

(c) Which of the two is electropositive?

Answer: ElementX is electropositive. Electropositive elements tend to lose electrons easily. Since X has 1 electron in its outermost shell, it will likely lose that electron and form a cation, making it electropositive.

ElementY, on the other hand, is electronegative, as it tends to gain electrons to complete its outer shell.

3. a) Which of the following flowers will have higher possibility of self-pollination?

Mustard, Papaya, Watermelon, Hibiscus

Answer: Mustard flowers have a higher possibility of self-pollination due to their structure, while papaya, watermelon, and hibiscus mainly rely on cross-pollination.

b) List the two reproductive parts of a bisexual flower.

Answer:Stamens (Male reproductive part) andPistil (Female reproductive part)

4. Which one of the two multicellular organisms - Spirogyra and Planaria reproduces by regeneration and why? Give an example of any other organism which can also reproduce by the same process.

Answer:Planaria reproduces by regeneration. This means that if a p